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Matematik Tambahan - Tingkatan 5 - Bantuan Kerjarumah
 Online Tutoring : Forum : Bantuan Kerjarumah (Tingkatan 5) : Matematik Tambahan - Tingkatan 5 - Bantuan Kerjarumah
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.deathscythe
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Joined: 16 September 2005
Location: Malaysia
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Posted: 18 September 2005 at 12:49pm | IP Logged Quote .deathscythe

sila tolong  tooolooong !!!!!!!

jika perimeter sebuah segi empat ialah 100m, hitung luas maksimum segi empat itu.

can given me answer lengkap tak

thank you 



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Guanz
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Joined: 21 September 2005
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Posted: 21 September 2005 at 9:28pm | IP Logged Quote Guanz

jika perimeter segi empat itu ialah 100m, luas maksimumnya ialah 625m kerana

100/4 = 25m satu tepian

25 X 25 = 625m

Jika segi empat itu ialah segi empat tepat, luas maksimumnya juga adalah 625m kerana

Eg.

(20+20)+(30+30)m = 100m

20 X 30 = 600m

Eg. 2

(40+40)+(10+10)m = 100m

40 X 10 = 400m

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Piggy2004
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Posted: 26 September 2005 at 3:36pm | IP Logged Quote Piggy2004

Betul.Mengapa dia kata jawapan luas bagi segiempat itu ialah luas maksimum?Ini kerana segiempat sama mempunyai luas maksimum.Kalau tak percaya,cuba soalan ini:

Ali diberi peluang untuk memiliki sebidang tanah oleh ayahnya.Untuk megetahui kepintaran anaknya itu,ayahnya telah memberikan dia seutas tali yang panjangnya 360m untuk dijadikan perimeter tapak barunya itu.Apakah yang harus dibuat oleh Ali untuk mendapat kawasan tanah yang paling luas?

       Ali           Bapa Ali
                         


Edited by Piggy2004 on 26 September 2005 at 3:40pm


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Adeng
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Posted: 07 October 2005 at 3:30pm | IP Logged Quote Adeng

Ok the question is:

If the perimeter of a rectangle is 100m, determine the maximum area of the rectangle.

This is my solution:

Let x = width of rectangle   and   y = length of rectangle

Perimeter means sum of all sides:

2x + 2y = 100

x + y = 50

Let A be the area of rectangle:

A = xy

A = x(50 - x)

A = 50x - x

Differentiate A with respect to x:

dA
dx
 = 50 - 2x

When A is maximum,

dA
dx
 = 0

50 - 2x = 0

x = 25

When x=25, y=25

Maximum area = 25  25 = 625 m

Solved!

 

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