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Topic Topic: Momentum-----help me please Post ReplyNew Question
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Joined: 02 October 2007
Posts: 1
Posted: 02 October 2007 at 5:18pm | IP Logged Quote Gotomaki

1)a kitten of mass 0.06 kg leaps at 30 to the horizontal out of a toy truck of mass 1.2 kg causing it to move over horizontal ground at 4m/s.At what speed did the kitten leap?

The answer is 9.2m/s(but i don't know how to work out)

2)A particle of mass 5m moving with speed v explodes and splits into two pieves with masses of 2m and 3m.The lighter piece continues to move in the original directin with speed 5v relative to the heavier piece.What us the actual speed of the lighter piece?

The answer is 4v(but ii don't know how to work out)

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Joined: 29 September 2007
Location: India
Posts: 4
Posted: 04 October 2007 at 12:13am | IP Logged Quote Prasadb

Answer (2).

This problem  is solved using the principle of Conservation Of momentum i.e. initial momentum = Final momentum

Initial momentum = 5v

Let us assume the speed of heavier piece is Vm/s.

The speed of lighter piece= 5v relative to heavier piece i.e.

                                     = V +5v

Final momentum = 2(V+5v) + 3V

Now 5v=2(V+5v) + 3V as per the Conserv.Of Momentum law

solving which we get V=-v

 Speed of lighter piece = V+5v=4v m/s


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