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Topic Topic: projectile motion Post ReplyNew Question
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Joined: 05October2007
Location: United States
Posts: 1
Posted: 05October2007 at 7:49am | IP Logged Quote Bxangel

I need help with this problem: A small plane flying food to a snow bound herd of cattle comes down to a 100.0 m elevation where, traveling at 110.0 km/h in a straight and level flight , the pilot releases a bail of hay. Find the time to hit the ground, the horizontal distance traveled, the vertical velocity acquired, and the velocity of impact. Somebody plz respond.


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Joined: 29September2007
Location: India
Posts: 4
Posted: 06October2007 at 10:14pm | IP Logged Quote Prasadb

Horizontal velocity: 110 km/h=110x 1000/3600= 30.56 m/sec


Initial Vertical velocity will be zero  i.e.  U(v)=0 

Vertical Displacement is same as elevation s = 100m


Now use the equation, s = ut+ at^2

a= acceleration due to gravity =g=9.8m/s^2,  t is the time to hit the ground.


Hence 100 =1/2X 9.8Xt^2

(1) t = 4.52 sec


(2) Vertical velocity acquired, V(v)= U(v)+ at

 V=9.8X4.52= 44.3m/s


(3) In the absence of any acceleration in the horizontal direction,

Horizontal distance traveled = Horizontal velocity X time


 =30.56X 4.52=



(4) Velocity of impact = sqrt(30.56^2+44.3^2)

= 53.82m/s

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