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Pure Mathematics
 Online Tutoring : Forum : Homework Help - Mathematics : Pure Mathematics
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Gabbym
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Posted: 09 October 2007 at 10:41am | IP Logged Quote Gabbym

SOVING AN EQUATION BY ELIMINATION WITH THREE VARIABLES        

2X-Y+Z=3
X+2Y+Z=12
4X-3Y+Z=1


HOW DO i GO ABOUT ANSWERING THIS FOR X,Y, AND z
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Gabbym
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Posted: 09 October 2007 at 10:44am | IP Logged Quote Gabbym

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Amitjha
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Posted: 20 October 2007 at 11:34am | IP Logged Quote Amitjha

hey i ve solved it, but its lengthy . do u rally want me 2 solve it 4 u and explain also? pls me or mail me at akjha5000@yahoo.co.in

thx



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Alianna22
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Posted: 26 October 2007 at 10:04am | IP Logged Quote Alianna22

First to solve this problem by using elimination you are going to need to choose which variable (letter) you want to work with.  I choose "z" because the only thing you will need to do is mulitple the equation(s) by a negative instead of a negative and a number like "x" and "y".

So, let's make pairs to eliminate z: I choose (1,2) (1,3)

2x-y+z=3 (1 stays the same but what do we have to do to 2 to eliminate "z".. multiply it by a -)

-(x+2y+z=12)

So the new equation becomes

2x-y+z=3

-x-2y-z=-12

Now add them together and ''z'' is gone (x-3y=-9)

Now, do the same for (1,3) and you should get (-2x+2y=2)

Now take x-3y=-9 and -2x+2y=2 and solve for "x" or "y".

"x" should = 3 and "y" should = 4

Take and plug both of those in the original equation (1, 2, or 3) and solve for "z". 

You should get "z" = 1

Now, check this on all the equations by plugging in the values.

Example 2(3)-(4)+1=3 AKA 2x-y+x=3

Answer

(3,4,1)

 

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