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Physics
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Weight of submerged object Check your score
  Play           Question 135 of 170 in this category.    

M is a cube-shaped object with 10 cm sides. The density of M is 5 g/cm.  M is placed on a weight scale and both objects are fully submerged in water. By assuming water density as  1 g/cm  and gravitational acceleration as  10 m/s ,  what will be the weight of M as measured by the scale?
 
A.
25 N
B.
30 N
C.
35 N
D.
40 N
E.
45 N
F.
50 N

 
  * Quiz question created by Beka on 19 July 2005 at 2:26pm

 
 
 
 
 
 

 




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Weight of submerged object is reduced by buoyant force


Performing all calculations in SI :-

Volume of M = 0.1 m  0.1 m  0.1 m = 0.001 m

Mass of M = 0.001 m  5000 kg/m = 5 kg

Weight of M = 5 kg  10 m/s = 50 N

This is the normal weight of M. Underwater, buoyant force pushes upwards and reduces its weight. According to Bernoulli's principle, magnitude of buoyant force equals the weight of the displaced liquid. Hence :-

Volume of displaced water = Volume of M =  0.001 m

Mass of displaced water = 0.001 m  1000 kg/m = 1 kg

Weight of displaced water = 1 kg  10 m/s = 10 N

Buoyant Force = Weight of displaced water = 10 N

Therefore the normal weight of M is reduced by 10 N.

The measured weight = 50 N - 10 N = 40 N

 



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